Graph of a particle in parabolic path

[Jahnavi]

Homework Statement

Homework Equations

The Attempt at a Solution

I don't understand what is y-axis representing ? What is V(x) ? Is it potential energy ?

Since the graph is a parabola , V(x) = kx²

I don't know how to proceed further .

 

[haruspex]

Is it potential energy ?

I think it must be, given the choice of answers.

 

[Jahnavi]

I think it must be, given the choice of answers.

OK . V(x) is zero (minimum ) at x= 0 . x = 0 represents position of equilibrium .

How to distinguish between a) and b) ? Both represent SHM

 

[ehild]

The problem says that the particle follows the parabolic path shown, and the arrow points to the initial position of the particle, from where it is released from rest. Which function corresponds to that initial condition?

 

[Jahnavi]

The problem says that the particle follows the parabolic path shown, and the arrow points to the initial position of the particle, from where it is released from rest. Which function corresponds to that initial condition?

The parabolic shape in the graph represents the variation of V(x) with x . It does not represent the path .

Is the parabola representing V(x) or the actual path of the particle ? These two are different things

.Or is that the parabola is representing the actual path as well the variation of potential energy ?

If it is the actual path then option B) makes sense as it represents the cosine curve where particle is as it's extreme position.

 

[ehild]

"A particle of mass m is released from rest and follows a parabolic path as shown. " What do you think it means?
You can imagine that the particle moves in a well of parabolic cross section. And the potential energy is proportional to the height,
Anyway, the particle starts from rest. Which graphs starts with zero slop?

 

[Jahnavi]

Thanks !