Graph r(t) = <t^2, cos t, sin t>

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SUMMARY

The discussion focuses on graphing the vector function r(t) = . Participants clarify that the curve is constrained to a unit cylinder defined by the equation y² + z² = 1, with the parameter t representing movement along the x-axis starting from x = 0. The implied range for x is x > 0, while y and z are limited to the interval [-1, 1]. Various graphing utilities were suggested, and the importance of understanding the parameter elimination technique for visualizing the curve in different coordinate planes was emphasized.

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r(t)= <t^2, cost, sint>

Does anyone have a graphing program to make a picture of this, thanks.
 
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crazynut52 said:
r(t)= <t^2, cost, sint>

Does anyone have a graphing program to make a picture of this, thanks.

What kind of range are you looking for?

I assume this is a vector field?
 
its a curve of that function. I'm not sure on the range, I guess just enough to show the pattern. I believe it is a cos sin circle coming out the x axis.
 
Try this:

http://graphical.shacknet.nu/image1.jpg
 
Last edited by a moderator:
The implied range is that x>0, and that y and z must both be between -1 and 1 (inclusive). I don't have a graphing utility handy, but what I would do is find the 2D curve in each coordinate plane by eliminating the parameter. So, in the xy plane, you have y(x)=arccos(x1/2), in the xz plane you have z(x)=arcsin(x1/2), and in the yz plane you have y2+z2=1.

Basically, the curve is constrained to the unit cylinder y2+z2=1, and as it goes around it moves forward on the x-axis, starting from x=0.
 
Tom Mattson said:
The implied range is that x>0, and that y and z must both be between -1 and 1 (inclusive). I don't have a graphing utility handy, but what I would do is find the 2D curve in each coordinate plane by eliminating the parameter. So, in the xy plane, you have y(x)=arccos(x1/2), in the xz plane you have z(x)=arcsin(x1/2), and in the yz plane you have y2+z2=1.

Basically, the curve is constrained to the unit cylinder y2+z2=1, and as it goes around it moves forward on the x-axis, starting from x=0.

My plot seems to agree.
 
If you need a larger range, just request it.
 
graphic7 said:
If you need a larger range, just request it.

There is no larger range. The implied range that I stated is the maximal range.
 
Tom Mattson said:
There is no larger range. The implied range that I stated is the maximal range.

Only in the y and z directions, though. I just replotted from 0 to 1000 and you really get to see the unit cyclinder take form.
 
Last edited:
  • #10
graphic7 said:
Only in the y and z directions, though. I just replotted from -1000 to 1000 and you really get to see the unit cyclinder take form.

Ah, I see what you're saying. You mean a larger range in your picture. What I was saying is that the range implied by the equations is the maximal range, and that if there is any modification to that range in the problem, it can only be smaller, not bigger.
 
  • #11
Tom Mattson said:
Ah, I see what you're saying. You mean a larger range in your picture. What I was saying is that the range implied by the equations is the maximal range, and that if there is any modification to that range in the problem, it can only be smaller, not bigger.

Ah, sorry for the confusion.
 

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