Graphing acceleration versus theta to find gravity

Click For Summary
To find the acceleration due to gravity (g) using the slope from a graph of acceleration versus theta, the equation a = g*sin(theta) can be rearranged to express the slope as g when plotting acceleration (a) on the y-axis and sin(theta) on the x-axis. The line should ideally pass through the origin, but if there is a positive y-intercept (b), it indicates potential experimental errors such as friction or systematic offsets. If the R² value is close to 1, the slope can be used to approximate g, but the intercept should be considered in the context of the experiment's accuracy. The discussion emphasizes the importance of understanding the relationship between the variables and the potential impact of errors on the results. Ultimately, the slope can be treated as an estimate for g, but caution is advised regarding the intercept's significance.
channel1
Messages
70
Reaction score
0

Homework Statement



using the equation a = g*sin(theta) where theta is in degrees

how do i find g using the slope from a graph plotting acceleration versus theta? (i have acceleration on the y-axis versus theta on the x axis)

Homework Equations



a = g*sin(theta) where theta is in degrees

The Attempt at a Solution



i was able to set it up as slope = y/x = a / theta = [g*sin(theta)] / theta
but I am totally stumped on how to use it since theta is changing but the slope and g are constant...
 
Physics news on Phys.org
What is the general equation for a line passing through the origin in the X-Y plane?
 
the question is to find g, i already HAVE the slope if that's what youre getting at. i need to use the value i have for the slope to find g
 
channel1 said:
the question is to find g, i already HAVE the slope if that's what youre getting at. i need to use the value i have for the slope to find g

It's not quite what I'm getting at :smile:

What's the general form?
 
is standard form alright?

y = mx + b
 
channel1 said:
is standard form alright?

y = mx + b

Okay, since the line will pass through the origin, b = 0 and you have just y = m*x. Now, let's identify each of the terms of your acceleration equation with the the standard form:

a --> y
m --> g {this is what you're trying to find}
x --> sin(θ)

So, if you were to plot a on the y-axis, and sin(θ) on the x-axis...
 
the line doesn't pass through the origin though it starts at a positive value for b right above the origin
 
channel1 said:
the line doesn't pass through the origin though it starts at a positive value for b right above the origin

If you're plotting from collected experimental data, there's bound to be some offset due to human error, systematic error, or random error in the collection process. Some small amount of friction, for example, could bias the results.

How large is the offset compared to the range of data?
 
the data was given to us, its a exercise to help us learn how to use excel. by offset do you mean the R^2 value? its pretty close to 1. so do i just ignore the value for b and say the slope is the value for gravity? (thats why I am having such trouble i have no way to check my answer because they could be assigning the value for gravity to be anything as far as i know so I am not sure if I am supposed to manipulate formulas somehow to obtain 9.81 or if my value for "m" can be used for "g" even though i have a positive value for b)
 
  • #10
channel1 said:
the data was given to us, its a exercise to help us learn how to use excel. by offset do you mean the R^2 value? its pretty close to 1. so do i just ignore the value for b and say the slope is the value for gravity? (thats why I am having such trouble i have no way to check my answer because they could be assigning the value for gravity to be anything as far as i know so I am not sure if I am supposed to manipulate formulas somehow to obtain 9.81 or if my value for "m" can be used for "g" even though i have a positive value for b)

Since I haven't seen the data or a full description of the problem or experiment its supposed to represent, there's not much I can comment on with any certainty. It could be that if friction is involved a straight line fit to the data will be problematical. Friction will have the most effect at small incline angles when normal force is maximal.
 
  • #11
neither have i really. we're given a table of data including theta and "a=gsin(theta)" and we're told to use excel to obtain the slope to find g
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
46
Views
4K
  • · Replies 9 ·
Replies
9
Views
808
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
55
Views
5K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
1K