Graphing the Curl of -Cx\vec{z} on the xz plane

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SUMMARY

The curl of the vector field ##E = -Cx\hat{z}## is calculated to be ##C\hat{y}##, indicating that it is constant across the xz plane. The relevant equation used for this calculation is the curl operator, represented as ∇xE. The discussion confirms that all other components of the curl are zero, affirming that the curl does not vary with position on the xz plane.

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scorpius1782
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I posted the divergence of this earlier but thought I should post the curl separately.

Homework Statement



Find the curl of ##E=-Cx\hat{z}##


Homework Equations


∇xE=##[\frac{∂E_z}{∂y}-\frac{∂E_y}{∂z}]\hat{x}+[\frac{∂E_x}{∂z}-\frac{∂E_z}{∂x}]\hat{y}+[\frac{∂E_y}{∂x}-\frac{∂E_x}{∂y}]\hat{z}##


The Attempt at a Solution



Since there's only a z component
∇xE=##-\frac{∂E_z}{∂x}=C\hat{y}##

I'm suppose to graph this onto the xz plane. But, isn't all the same throughout the plane? I feel like maybe I missed a component from the derivatives but I think all the rest are 0, right?

Thanks for any guidance.
 
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Yes, that is correct. For ever point the curl of [itex]-Cx\vec{z}[/itex] is the constant [itex]C\vec{y}[/itex].
 

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