Graphing the Power dissipated in a resistor

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SUMMARY

The discussion focuses on graphing the power dissipated in a resistor within two types of series circuits: one with a constant voltage source and a variable resistor, and another with a constant current source and a variable resistor. The power equation utilized relates the resistance (R) to the power (P) dissipated in the circuit. The participant expresses confidence in their approach but seeks validation of their method for accuracy.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with power equations in electrical circuits
  • Knowledge of series circuit configurations
  • Basic graphing techniques for electrical parameters
NEXT STEPS
  • Study the power equation P = V^2 / R for constant voltage circuits
  • Explore the power equation P = I^2 * R for constant current circuits
  • Learn how to graph electrical parameters using software tools like MATLAB or Python's Matplotlib
  • Investigate methods for verifying circuit calculations through simulation tools like LTspice
USEFUL FOR

Electrical engineering students, hobbyists working with circuits, and educators teaching concepts of power dissipation in resistors.

guyvsdcsniper
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Homework Statement
Graph the power dissipated in each resistor as a function of its resistance.
Relevant Equations
P=VI
I am solving #5 in the attached image.

So I am graphing the power dissipated by a series circuit which : (a) Contains a constant voltage source and a variable resistor, R (b) Contains a constant current source and a variable resistor.

It makes sense to me to just use the power equation that allows me to define the constant from each series and the power will be determined by what relationship R shares with P in said equation.

Just wondering if I have the right approach.

IMG_098E9BFE4AFE-1.jpeg
 
Physics news on Phys.org
Looks good to me. Why are you doubting your method? How could you verify yourself that you are correct?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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