Graphing Velocity vs Time for a Falling Rope

  • Thread starter Thread starter knightpraetor
  • Start date Start date
  • Tags Tags
    Rope Velocity
Click For Summary

Homework Help Overview

The discussion revolves around graphing the velocity versus time for a falling rope, specifically in the context of a physical scenario where one end of the rope is cut and allowed to fall. The original poster expresses uncertainty about how to graph this relationship numerically using Maple and seeks intuition about the expected graph shape.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the integration of differential equations to derive velocity as a function of time. Questions arise about which equations to integrate and how to express velocity in terms of time rather than position. There is also a consideration of the role of tension in the rope affecting acceleration and velocity over time.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the equations involved. Some guidance is offered regarding the use of Maple for graphing, but there is no explicit consensus on the approach to take for deriving the velocity function.

Contextual Notes

There is mention of potential difficulties in solving the differential equations by hand and the complexity of the problem, which may affect the ability to graph the velocity versus time accurately. The original poster's notation for derivatives (dot and double dot) is clarified, indicating a need for understanding the mathematical representation of the problem.

knightpraetor
Messages
18
Reaction score
0
SO i basically need to know what the graph of velocity vs time is..and I'm supposed ot do this numerically using maple...though if anyone has some basic intuition about what the graph should look like, even that would be nice.

Anyways, I'm unsure of how to graph it

Basically i have [tex]x_dot^2 = \frac {g(2bx-x^2)}{b-x}[/tex] and that
[tex]x_doubledot = g + \frac {g(2bx-x^2)}{2(b-x)^2}[/tex]

and i thought i could just integrate the first one and get a function relating x and t, and then use that in the second equation to get an equation for velocity in terms of just time...because otherwise how am i supposed to graph it.

Anyways, for those who are wondering this graph of velocity vs time is supposed to represent a simple physical problem of a rope whose ends are attached to two ends A and B on a ceiling..and then B is cut loose and allowed to fall. So i thought the greatest acceleration would occur at the beginning and decrease as more tension occurs in the rope during the later portions with a rapid falloff in velocity at the end.

ANyways, thoughts or ideas would be nice..not really sure what to do

ps- xdot = velocity and x double dot = acceleration
 
Physics news on Phys.org
Huh? What is dot and double dot supposed to be, a first and second time derivative?

It looks to me like they are first and second order autonomous differential equations. What is the problem with using Maple to graph them? Maple, I haven't really used it much, is supposed to have a really good differential plotter. If that is the part you are having trouble with, you could probably use Maple's help functions and figure it out.
 
yeah, dots are derivatives with respect to time..but which function do i integrate to get velocity? i mean i can integrate the second one (acceleration ) to get velocity, but even then, it's in terms of x rather than time..i want velocity versus time so how do i go about getting that
 
If you solved the second differential with respect to time you would get your velocity as a function of time and x, unless that is given to you. That looks like it is pretty crappy to solve by hand, so I don't know what the solution is, but Maple should be able to do it.

Looks like you have a second order differential of the form
[tex]\frac{d^2 x}{dt^2}+\frac{a_1}{a_2} \frac{dx}{dt} + {a_o}x = f(x)[/tex]
Some kind of vibration? I don't know, differentials are ugly.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
31
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
46
Views
7K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K