Graphs to find minimum days for meetings

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SUMMARY

The discussion focuses on determining the minimum number of days required for nine students to meet across eight committees without overlapping members. The solution involves graph coloring, where vertices represent committees and edges indicate shared members. The conclusion is that a minimum of four colors is necessary, as established by the Appel-Haken Theorem, to ensure no two committees with common members meet on the same day. The presence of a clique among the first four committees confirms that three colors are insufficient for proper coloring.

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  • Graph theory fundamentals
  • Understanding of graph coloring concepts
  • Familiarity with the Appel-Haken Theorem
  • Basic knowledge of cliques in graph theory
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  • Explore the Appel-Haken Theorem in detail
  • Learn about clique structures in graph theory
  • Investigate algorithms for graph coloring optimization
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Mathematicians, computer scientists, and students studying graph theory or combinatorial optimization, particularly those interested in scheduling and resource allocation problems.

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Homework Statement


Nine students A, B,..., I serve as members on eight committees, as follows.

Committee 1: A, B, C, D
Committee 2: A, C, D, E
Committee 3: B, D, F, G
Committee 4: C, F, G, H
Committee 5: A, H
Committee 6: H, I
Committee 7: G, H
Committee 8: E, I

Each committee is to meet for a day. No two committees with a member in common can meet on the same day. Use a colouring of a suitable graph to find the least number of days in which the meetings can take place.

Homework Equations


None

The Attempt at a Solution


Let 1,2...,8 be vertices on a graph and let an edge be between two vertices if those committees share a student. If an edge exists between two vertices, then those vertices must be coloured differently

I've drawn out the graph properly, and is 4 (the number of colours used to colour the graph) the minimum no of days needed for the committees to meet? I know that 4 can be used by the Appel-Haken Theorem. i can't see a way to colour the graph with only 3 colours.
Graph1.jpg
EDIT: just realized that 2 and 5 should be connected on the graph but it doesn't make any difference to the colouring.

thanks for any help :)
 
Last edited:
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Well, you have a clique (all nodes are connected to each other): \{1, 2, 3, 4\} so you need at least 4 colors, with 3 colors you can not even color your clique.
 

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