Gravitation multiple particle system

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The discussion revolves around calculating the work done on sphere B in a gravitational system involving three spheres with given masses and distances. The initial approach using the formula W=Fd is deemed inappropriate due to the variable nature of gravitational forces during the movement of sphere B. Instead, participants suggest using an energy approach to determine the change in energy of sphere B, which relates to the work done by gravitational forces. The net gravitational force calculation yields an answer of -1.25e-12 J, but the expected result is 0.50 pJ. The conversation emphasizes understanding the relationship between energy changes and work done by conservative forces in a dynamic system.
Puchinita5
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Homework Statement



The three spheres in Fig. 13-45, with masses ma=80g ,mb=10g and mc=20g, have their centers on a common line, with L=12 cm and d=4cm. You move sphere B along the line until its center-to-center separation from C is d=4cm. How much work is done on sphere B (a) by you and (b) by the net gravitational force on B due to spheres A and C

Homework Equations


http://edugen.wiley.com/edugen/courses/crs1650/art/images/halliday8019c13/image_t/tfg045.gif

The Attempt at a Solution


I figured if W=Fd...then I started with trying to figure out the Force on particle b.
F= Gm1m2/rr so...
-G(.01)(.08)/(.04^2) + G(.01)(.02)/(.08^2) which gave me -3.13e-11...i then multiplied this by the distance d=.04...this gave me = -1.25e-12 J...

however the answer is .50 pJ

that's for net gravitational force, I'm not really sure how they mean for me to calculate the force by me?
 
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Puchinita5 said:

Homework Statement



The three spheres in Fig. 13-45, with masses ma=80g ,mb=10g and mc=20g, have their centers on a common line, with L=12 cm and d=4cm. You move sphere B along the line until its center-to-center separation from C is d=4cm. How much work is done on sphere B (a) by you and (b) by the net gravitational force on B due to spheres A and C

Homework Equations


http://edugen.wiley.com/edugen/courses/crs1650/art/images/halliday8019c13/image_t/tfg045.gif


The Attempt at a Solution


I figured if W=Fd.

No, I don't believe that will work here. That is the formula for work done by a constant force, but here the force on the moving particle is changing as it moves.

I would suggest using an energy approach here. What is the change in energy of the moving particle? And think about these questions: How is that energy change related to the work done? What is the work done by a conservative force?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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