Gravitation multiple particle system

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SUMMARY

The discussion focuses on calculating the work done on sphere B in a gravitational multiple particle system involving three spheres with masses ma=80g, mb=10g, and mc=20g. The net gravitational force on sphere B is calculated using Newton's law of universal gravitation, resulting in a force of -3.13e-11 N, leading to a net work of -1.25e-12 J. However, the correct answer for the net gravitational force is 0.50 pJ. The discussion emphasizes the need for an energy approach to determine the work done by the user on sphere B, as the gravitational force acting on it changes during its movement.

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Puchinita5
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Homework Statement



The three spheres in Fig. 13-45, with masses ma=80g ,mb=10g and mc=20g, have their centers on a common line, with L=12 cm and d=4cm. You move sphere B along the line until its center-to-center separation from C is d=4cm. How much work is done on sphere B (a) by you and (b) by the net gravitational force on B due to spheres A and C

Homework Equations


http://edugen.wiley.com/edugen/courses/crs1650/art/images/halliday8019c13/image_t/tfg045.gif

The Attempt at a Solution


I figured if W=Fd...then I started with trying to figure out the Force on particle b.
F= Gm1m2/rr so...
-G(.01)(.08)/(.04^2) + G(.01)(.02)/(.08^2) which gave me -3.13e-11...i then multiplied this by the distance d=.04...this gave me = -1.25e-12 J...

however the answer is .50 pJ

that's for net gravitational force, I'm not really sure how they mean for me to calculate the force by me?
 
Last edited:
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Puchinita5 said:

Homework Statement



The three spheres in Fig. 13-45, with masses ma=80g ,mb=10g and mc=20g, have their centers on a common line, with L=12 cm and d=4cm. You move sphere B along the line until its center-to-center separation from C is d=4cm. How much work is done on sphere B (a) by you and (b) by the net gravitational force on B due to spheres A and C

Homework Equations


http://edugen.wiley.com/edugen/courses/crs1650/art/images/halliday8019c13/image_t/tfg045.gif


The Attempt at a Solution


I figured if W=Fd.

No, I don't believe that will work here. That is the formula for work done by a constant force, but here the force on the moving particle is changing as it moves.

I would suggest using an energy approach here. What is the change in energy of the moving particle? And think about these questions: How is that energy change related to the work done? What is the work done by a conservative force?
 

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