Gravitational Fields: Earth's Rotation & UK Latitude 53

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SUMMARY

The discussion focuses on calculating the rotational speed of the Earth at latitude 53 degrees in the UK and its effect on gravitational force. The user attempted to determine the length of a day using the formula w = theta/time, resulting in a 59-minute day, which prompted questions about the accuracy of the calculation. The conversation emphasizes the relationship between angular velocity (w), linear velocity (v), and radius (r) in understanding gravitational fields and rotational dynamics.

PREREQUISITES
  • Understanding of angular velocity and its calculation using w = theta/time
  • Familiarity with linear velocity concepts in circular motion
  • Knowledge of gravitational forces and their effects on objects in motion
  • Basic trigonometry for calculating angles and distances on a sphere
NEXT STEPS
  • Research the effects of Earth's rotation on gravitational force at different latitudes
  • Learn about the Coriolis effect and its implications on weather patterns
  • Explore the mathematics of circular motion and its applications in physics
  • Investigate the historical context of Earth's rotational speed measurements
USEFUL FOR

Students studying physics, particularly those interested in gravitational fields, rotational dynamics, and the effects of Earth's rotation on objects at various latitudes.

rugby123
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Homework Statement


the Earth's gravitational field is sufficiently strong enough to keep us on it- even though we are traveling in a circle on its surface. But how fast would we be spinning before we started to fall off? What about at latitude 53 (UK)? and how long would a day be?


Homework Equations



w=theta/time
w=v/r

The Attempt at a Solution


i got 59 minutes for the day using 2pi/1.75x10-3
 
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Is that your result for the equator or the UK latitude?

Either way, it doesn't look right to me. Can you show your work?
 

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