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Gravitational force between 2 particles

  • Thread starter clope023
  • Start date
  • #1
987
123
1. Homework Statement

A uniform, solid, 1900kg sphere has a radius of 5.00m. Find the gravitational force this sphere exerts on a 1.50kg point mass placed at the following distances from the center of the sphere: (a) 5.01m , and (b) 2.45m.


2. Homework Equations

Fg = GMm/r^2

volume of sphere = (4/3)piR^3

density of sphere = M/volume

ratio of point mass to shere:

M/msphere = (4/3piRM^3)/(4/3piRsphere^3)

Mmass = msphere(Rmass/Rsphere)^3

G(M)(mmass)/r^2 = Gmass(msphere(rmass/rsphere)^3)/Rsphere^2

= G(mmass)(msphere)rmass/rsphere




3. The Attempt at a Solution

Fg = G(1900)(1.50)(5.01)/5^2 = 3.8x10^-7

Fg = G(1900)(1.50)/5^2 = 8x10^-8

nothing, I'm not sure what I'm doing wrong, any help is greatly appreciated.
 

Answers and Replies

  • #2
458
0
1. Homework Statement

A uniform, solid, 1900kg sphere has a radius of 5.00m. Find the gravitational force this sphere exerts on a 1.50kg point mass placed at the following distances from the center of the sphere: (a) 5.01m , and (b) 2.45m.


2. Homework Equations

Fg = GMm/r^2

volume of sphere = (4/3)piR^3

density of sphere = M/volume

ratio of point mass to shere:

M/msphere = (4/3piRM^3)/(4/3piRsphere^3)

Mmass = msphere(Rmass/Rsphere)^3

G(M)(mmass)/r^2 = Gmass(msphere(rmass/rsphere)^3)/Rsphere^2

= G(mmass)(msphere)rmass/rsphere




3. The Attempt at a Solution

Fg = G(1900)(1.50)(5.01)/5^2 = 3.8x10^-7

Fg = G(1900)(1.50)/5^2 = 8x10^-8

nothing, I'm not sure what I'm doing wrong, any help is greatly appreciated.
Where are the 5^2 coming from?
 
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