PeterDonis
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Again you are missing the key point: in the starting configuration of the system, it holds zero gravitational potential energy. The total mass is just ##m + M##; there is no extra "potential energy" term in there.Lok said:I used the Sun and Sag A* as the initial bodies to underline the massive amount of energy that such a system holds as potential energy.
It is true that as the Sun falls, it gains kinetic energy, and to compensate it loses gravitational potential energy, i.e., as I have said, its gravitational potential energy becomes negative, and gets more negative as it falls. But viewing this as somehow using gravitational potential energy that was "stored" in the initial configuration is not helpful, because it makes you think there is some kind of issue involved with the total mass just being ##m + M##. There isn't. Once you properly understand this, the question you think you are asking simply evaporates.
That's wrong. The formula does not depend on the "smallest distance", it depends on the actual distance. At the start it is zero because the actual distance is effectively infinity. At the end it is a negative value that exactly cancels the Sun's kinetic energy.Lok said:In the OP I used the as in Wiki weirdly formulate value for Gravitational potential energy.
U=-GMm/R, where R is the smallest distance that can be attained by the masses
And your insistence on looking at it this way is why this thread keeps going on--the correct answer is staring you in the face and you are refusing to accept it.Lok said:I would not state that KE cancels out GPE, but rather one transforms into another.
Which, again, is because you are refusing to accept the correct answer that is staring you in the face: the total mass is just ##m + M##, always, and what happens internally can't change it because the system is isolated. There is no "extra mass" anywhere.Lok said:either the extra 24% mass is a real thing, and this leaves me wondering where it is distributed in the initial state.
It is impossible for the Sun to not have KE in the final state. As I have already said, there is only one valid solution to this scenario. Talking as though there were other possibilities is simply wrong. And this error appears to be part of what is confusing you and keeping you from accepting the obvious correct answer.Lok said:Or it is a figment of equations and there should be no difference in outcome whether there is or there isn't KE in the final state.
Yes, because ##E_P = - E_K## so ##m + M + E_K + E_P = m + M##. This is the obvious correct answer that you are refusing to accept.Lok said:would those ##m+M+E_K+E_P## energy terms add to the mass of the box?
In the initial state, ##E_K = E_P = 0##. Which is just a special case of ##E_P = - E_K##; the latter is always true in this scenario.Lok said:If yes, how is that mass distributed in the initial state as the final state is less of an issue.
Sure, but in this scenario that is irrelevant, because PE exactly cancels out KE and there is no net contribution to the total mass. For KE to appear as "extra mass" in the total mass of the system you have to look at a different scenario in which PE and KE do not exactly cancel. And for such a scenario the total mass would not be ##m + M##, even at the start (although even here calling the KE "extra mass" can be misleading, since the total mass will be less than ##m + M##). If you want to discuss such scenarios, you can start a new thread to ask about one (for example, you could consider having the Sun in a circular orbit around Sag A at some finite radius).Lok said:KE does have a measurable mass via e.g. heat
That is because you keep talking as if there were some "extra mass" in this scenario, when there is none.Lok said:I am going for dark matter of course