Gravity and acceleration simple calculation

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Homework Help Overview

The discussion revolves around calculating initial speed and acceleration in the context of gravity and motion. Participants are exploring the application of kinematic equations to determine how an object falls from a height of 7 meters over a time period of 3 seconds.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correct interpretation of initial conditions, specifically whether to calculate initial speed or acceleration. There is an exploration of algebraic manipulation of the kinematic equation to isolate initial speed. Questions arise about the implications of negative values in the context of motion.

Discussion Status

The discussion is active, with participants providing algebraic insights and confirming calculations. Some guidance has been offered regarding rearranging formulas and interpreting results, but there is no explicit consensus on the broader implications of the calculations.

Contextual Notes

Participants are working within the constraints of a homework problem, with specific values for height, time, and gravitational acceleration. There is an ongoing exploration of related concepts, such as the effects of initial speed on distance over time.

forrestuv
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With this formula for distance calculation with gravity acceleration:

distance = 1/2 × acceleration × time^2 + intial speed × time

what Initial Acceleration does an object need to touch the ground in 3secs from 7meters of heigth?
what's the formula for that?

thx
 
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forrestuv said:
what Initial Acceleration does an object need to touch the ground in 3secs from 7meters of heigth?
I assume you want the initial speed, not acceleration. The acceleration of a falling body is fixed at 9.8 m/s^2.
what's the formula for that?
That formula will do. Just solve for the initial speed.
 
ops.. yes I need the initial speed..how to obtain that from the formula I posted?I'm a real noob in math :(
 
It's just a bit of algebra. Take a stab at it.

For a start, if you had A = B + C, how would you solve for C?
 
C=a-b ? :)
 
forrestuv said:
C=a-b ? :)
Exactly. So rearrange your formula accordingly.
 
distance = 1/2 × acceleration × time^2 + intial speed × time

ok so:

intial speed × time = distance - (1/2 × acceleration × time^2)

then:

initial speed = (distance - (1/2 × acceleration × time^2)) / time

is it right? :)
 
in my case:

h=7 mt
t=3 secs
g=9.8

initial speed = (distance - (1/2 × acceleration × time^2)) / time

initial speed= (h- (1/2 × g × t^2)) / t

(7-(0.5x9.8x9)) / 3

(7-44.1) / 3 = -12.3666

can you check if it is correct please ? :)
 
forrestuv said:
can you check if it is correct please ? :)
Yes, it's correct. The reason why it's negative is that you have to throw the object upwards for it to take that long to fall 7m. (If you just dropped it would take only 1.2 seconds to hit the floor.)

In your equation, you took down as positive.
 
  • #10
thxxxxxx!
I appreciated your help very very much :)
 
  • #11
Now I would like to obtain something impossible to calculate for me :)
I need to know the min Initial speed needed to have, at a certain time a distance greater than a number.

example:
if I throw a ball at an initial speed of 12 I want to be sure that at 2 secs the distance is greater than 8.
is it possible?

science fiction for me eheh :)
 
  • #12
alternatively:

Giving a fixed Initial Speed, If I want to double the distance at which the object will be at a certain time, how much should I increase time of?
 

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