Gravity Work & Power of a Lawn Mower & Motion of a Cart

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SUMMARY

The discussion focuses on calculating work and power in physics, specifically using the formulas for work (w = Fd cos(β)), power (P = w/t), and kinetic energy (KE = 1/2 mv²). Key calculations include determining the work done by gravity with a force of 350 Newtons over a distance of 2.00 meters, and the power of a lawn mower exerting 88 Newtons over a distance of 1.2 kilometers in 30 minutes. Additionally, the final velocity of a 15 kg cart pushed with a force of 105 Newtons over 10 meters is analyzed, along with its work and final kinetic energy.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with work-energy principles
  • Basic knowledge of power calculations in physics
  • Ability to manipulate equations involving force, distance, and time
NEXT STEPS
  • Study the concept of gravitational potential energy and its calculations
  • Learn about the relationship between force, mass, and acceleration using F = ma
  • Explore advanced applications of kinetic energy in real-world scenarios
  • Investigate the efficiency of machines, focusing on power output versus input
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in practical applications.

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Homework Statement



1a) Find the work done by the force of gravity.
Given- Force = 350 Newtons
distance = 2.00
1b) find the power of a lawn mower the time is 30 min and the force is 88 Newtons and the distance is 1.2 km

2a) a 15 kg cart starts from rest, travels 10 meters with a force of 105 Newtons. what is the final velocity?

2b) What is the carts work while pushing down the aisle
2c) what is the carts final kinetic energy?

Homework Equations



P= w/t , KE= 1/2mv^2, w=Fdcos(beta)

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