Green's Theorem and Conservative Fields

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Discussion Overview

The discussion revolves around the vector field defined by x^2yi + xy^2j and its characteristics in relation to Green's Theorem and conservative fields. Participants explore the conditions under which the field may behave like a conservative field locally, particularly along the line y = x, and the possibility of approximating a scalar field whose gradient resembles the vector field in that region.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant asserts that the vector field is not conservative due to the condition dq/dx - dp/dy = y^2 - x^2 ≠ 0.
  • Another participant suggests that along the line y = x, the field behaves like a conservative field and questions if this is true.
  • A participant proposes that it is possible to integrate along the y = x line to obtain values of a scalar field and generalize it so that its gradient aligns with the vector field.
  • However, a different participant challenges the idea that the field is parallel to the y = x line, indicating a misunderstanding of the previous points.
  • One participant counters that locally along the y = x line, the field does exhibit parallel behavior.

Areas of Agreement / Disagreement

Participants express differing views on whether the vector field is parallel to the y = x line and whether it can be treated as conservative in that region. The discussion remains unresolved regarding the nature of the field along that line.

Contextual Notes

There are assumptions regarding the behavior of the vector field along specific lines and the conditions under which it may be approximated by a scalar field. The discussion does not resolve the mathematical steps required to fully establish these claims.

n1person
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So let's say we have the vector field x^2yi+xy^2j, obviously the field is not conservative since dq/dx-dp/dy=y^2-x^2=/=0

however, let's say we wanted to find where locally the field would behave like a potential field, so we set y^2-x^2=0, so y=x (along the y=x line the field behaves like a conservative field). So my question is, a) is this true? b) is there some way to get an approximate scalar field whose gradiant behaves like the vector field locally along the y=x line?

Just something I was pondering.
 
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Yes.

Since your field is parallel to y=x line at all points, you can integrate along the line and get values of the scalar field along that line, and then generalize it somehow so that its gradient points in the direction of the field.
 
hamster143 said:
Yes.

Since your field is parallel to y=x line at all points, you can integrate along the line and get values of the scalar field along that line, and then generalize it somehow so that its gradient points in the direction of the field.

But his field isn't parallel to the y = x line. Not that I understand what you are getting at anyway...
 
LCKurtz said:
But his field isn't parallel to the y = x line. Not that I understand what you are getting at anyway...

Locally along the y = x line it is.
 

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