Ground state of 7 electrons in infinite square well

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Homework Help Overview

The problem involves determining the ground state energy of a system of seven electrons confined in a one-dimensional infinite square well of length L. The context is rooted in quantum mechanics and the application of the Pauli exclusion principle.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the Pauli exclusion principle and the distribution of electrons across quantum states. There is an exploration of how many electrons can occupy each energy level and the implications for calculating total energy.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the quantum states available for the electrons. There is a recognition of a potential misunderstanding regarding the energy levels and the number of electrons that can occupy them.

Contextual Notes

There is a mention of confusion regarding the angular momentum number in the context of a one-dimensional infinite well, indicating a need for clarity on the nature of the states available to the electrons.

sabinscabin
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Homework Statement



Seven electrons are trapped in a one dimensional infinite square well of length L. What is the ground state energy of this system as a multiple of h2 / 8mL2?

Homework Equations


Energy of a single electron in state n is n2h2 / 8mL2

The Attempt at a Solution



Pauli exclusion principle says all 7 must have different quantum numbers.
starting from n = 1, we have L = 0 and mL = 0, and ms = -1/2 and 1/2, so there are two electrons in n = 1.
For n = 2, we have two electrons for L = 0
for L = 1, we have mL = -1, 0, 1, which means this subshell can hold 6 electrons. The remaining 3 electrons go into this subshell then.

Final tally: 2 electrons for n = 1 and 5 electrons for n = 2.

Total energy as a multiple of the given term then = 2*1^2 + 5*2^2 = 22.

Halliday Resnick says 44 for some reason. Can anybody spot my mistake?
 
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Hi sabinscabin,

sabinscabin said:

Homework Statement



Seven electrons are trapped in a one dimensional infinite square well of length L. What is the ground state energy of this system as a multiple of h2 / 8mL2?


Homework Equations


Energy of a single electron in state n is n2h2 / 8mL2


The Attempt at a Solution



Pauli exclusion principle says all 7 must have different quantum numbers.
starting from n = 1, we have L = 0 and mL = 0, and ms = -1/2 and 1/2, so there are two electrons in n = 1.
For n = 2, we have two electrons for L = 0
for L = 1, we have mL = -1, 0, 1, which means this subshell can hold 6 electrons. The remaining 3 electrons go into this subshell then.

Final tally: 2 electrons for n = 1 and 5 electrons for n = 2.

Total energy as a multiple of the given term then = 2*1^2 + 5*2^2 = 22.

Halliday Resnick says 44 for some reason. Can anybody spot my mistake?

For the 1-D infinite well, there are only two states for each energy level (corresponding to the two spin values).
 
ah thanks. That was incredibly stupid of me. It's in a square well so there's no angular momentum number since there's nothing to orbit.

D'oh!
 
No, not stupid. The important thing is to understand why something is wrong. If the test of stupidity is making a mistake, I'm in a lot of trouble.
 

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