Group Homomorphism: Prove Existence of Element a

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SUMMARY

The discussion centers on proving the existence of an element 'a' in a group G such that the map @: G⟶G defined by @(x) = aф(x) is a homomorphism. The key points include the definition of a homomorphism, which preserves group operations, and the requirement that @(e) must equal e. Participants emphasize the importance of using specific values and experimenting with the function ф to derive necessary properties and insights for the proof.

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  • Knowledge of function mapping in mathematical contexts.
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This discussion is beneficial for students of abstract algebra, mathematicians focusing on group theory, and anyone interested in understanding the foundational concepts of homomorphisms and their applications in mathematical proofs.

nadineM
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Homework Statement


Let G be a group with identity e and product ab for any elements a and b of G.
Let ф: G⟶G be a map such that Ф(a sub1)ф (a sub2)ф(a sub3) = ф(b sub1) ф(b sub2) ф(b sub3) whenever,
(a1) (a2)(a3) = e=(b1) (b2) (b3) for any(not necessarily distinct) elements a1 ,a2 ,a3, b1, b2, b3 of G.
Prove: There exists an element a in G such that the map @: G⟶G defined by @(x) = a ф(x) for every element x in G, is a homomorphism.

Homework Equations


Def: A homommorphism Ф from a group G to a group G is a mapping from G to G that preserves the group opperation. That is, Ф(ab) = Ф(a)Ф(b) for all a, b in G
Properties of elements under a homomorphism:
Ф carries the identity in G to the identity in G
Ф preserves inverses
*note that the Ф in this section is not the same as in the question...

The Attempt at a Solution



I really haven't got a clue on where to even begin to define "a" I am thinking that it needs to be triplet for example aea^(-1)...but I have no idea what to do or where to start...I am completely lost, can anyone give me a push in the right direction?:confused:
 
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Combine the facts "homomorphisms carry the identity in G to the identity in G" with "@(x) = aф(x)" to determine a.
 
I don't have a homomorphism though... I am not given the fact that Ф is a homomorphism?
 
AKG's point is that '@' is supposed to be a homomorphism, not the original function. So @(e) had better be e. Can we change symbols here?
 
Dick said:
AKG's point is that '@' is supposed to be a homomorphism, not the original function. So @(e) had better be e. Can we change symbols here?

OK thanks...I will work with that for a bit and see where I get...you can use what ever symbol you like i tried using gamma but couldn't get it to come up right...
 
It might help to experiment with ф to try and understand it better.

You have an identity it satisfies -- try plugging special values into those identities to see if you can deduce other facts about ф.

Try choosing a group and constructing an actual function ф that satisfies the listed properties.
 

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