Group Theory Help: Show (x*y*z^-1)^-1 = x*y^-1*z^-1

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SUMMARY

The discussion centers on proving the equation (x*y*z^-1)^-1 = x*y^-1*z^-1 within the context of group theory. The user initially computed the left side's inverse as x^-1*y^-1*z, but questioned the validity of their conclusion regarding the equality of both sides. The consensus confirms that the associativity law in group theory validates the equality, and the correct expression for the right side is indeed x*y^-1*z^-1, not zy^-1*x^-1.

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Homework Statement



Let G(*) be a group.
If x.y are elements of G show that (x*y*z^-1)^-1 = x*y^-1*x^-1

Homework Equations





The Attempt at a Solution


I first took the left side of the equation and computed the inverse and I got x^-1*y^-1*z
I then let this equal to the righthand side and concluded since the elements are in a group the associativity law holds they are equal. I was just wondering is this valid or am I missing something.
 
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I think the right side should be zy-1x-1, not xy-1x-1.
 

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