A population of wolves grows according to the function N(t)=(10N0)/(1+9e^(-t/4)), where t is in years and N0 is the initial amount. How long from t=0 will the population take to double?
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The Attempt at a Solution
Not sure if this is a completely calculus based question or not, but I threw it in here because it's listed in my calculus problems. Basically this one had stumped me, as I have no idea how to go about solving it. My first attempt was to try and find the initial population by using t=0, and then use that value to calculate the time it would take for it to double. This got me nowhere, for all I ended up with was N(t)=N0. I tried to use this by making N(t)=2N(t) and solving for t, but this only got close to the correct answer of 4ln10. Any help you guys can provide would be greatly appreciated on this question, thanks in advance