two infinite sheets of charge (one positive, one negative) are arranged parallel to each other and separated by a distance of 2m. a charge of 3 microcoulombs is realeased at the positive plate. when it reaches the negative plate it has a kinetic energy of 0.6 joules. what is the electric field between the plates
electric field of charge sheet E = sigma/2(epsilon_o) where sigma = charge density, epsilon_o = constant 8.85*10^-12
energy U = 1/2 CV^2 where C is capacitance, v is electric potential
C = Q/V where Q is charge, V is electric potential
The Attempt at a Solution
do i assume sigma as constant?
do i assume both sheets have the same electric field, so electric field between the sheets is the sum of the two?
how does the energy play a role in determining the electric field, the equation for electric field is already specified, and can be solved in terms of constants, assuming sigma is constant too.
if i use the energy and capacitance equation i get:
U = 1/2[(Q/V)(V^2)]
0.6 = QV/2
i am not sure how Q, V relate to electric field, I'm lost actually...