Gyroscopic precession force diagram

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SUMMARY

The discussion centers on gyroscopic precession, specifically the forces acting on a gyroscope's flywheel. Participants clarify that the torque from gravity does not cause the gyroscope to fall but instead results in precession. The normal force from the pivot balances the gravitational force, creating a force equilibrium necessary for stability. Additionally, the distinction between angular momentum and torque is emphasized, with angular momentum defined as ML²T⁻¹ and torque as ML²T⁻².

PREREQUISITES
  • Understanding of gyroscopic motion and precession
  • Familiarity with concepts of torque and angular momentum
  • Basic knowledge of force equilibrium in physics
  • Trigonometric relationships, particularly in relation to angles and their measures
NEXT STEPS
  • Explore the principles of gyroscopic precession in detail
  • Study the mathematical definitions and applications of torque and angular momentum
  • Investigate force equilibrium in rotating systems
  • Learn about the relationship between trigonometric functions and angular measures
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Physics students, educators, and enthusiasts interested in understanding gyroscopic dynamics and the underlying forces involved in rotational motion.

Elias Waranoi
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Hi, I've been learning about gyroscopic precession recently and I feel like I get it. I understand that when the flywheel of a gyroscope is spinning its angular moment plus the angular moment created by the torque from the force of gravity makes it turn. But I were thinking about the forces in a gyroscope and couldn't figure out what force is keeping the flywheel up. I know of the force of gravity and the normal force on the pivot connected to the rod connecting to the flywheel but to me that doesn't seem to be enough to keep the flywheel in the air. What's the other forces?

And bonus question, my physics book showed me that dθ = dL / L. I can understand this in a trigonometric way with tanθ = opposite / adjacent = dL / L. I can't make the connection between my knowledge in trigonometry and dθ = dL / L. The tanθ != dθ is what's bothering me.
 
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Elias Waranoi said:
Hi, I've been learning about gyroscopic precession recently and I feel like I get it. I understand that when the flywheel of a gyroscope is spinning its angular moment plus the angular moment created by the torque from the force of gravity makes it turn. But I were thinking about the forces in a gyroscope and couldn't figure out what force is keeping the flywheel up. I know of the force of gravity and the normal force on the pivot connected to the rod connecting to the flywheel but to me that doesn't seem to be enough to keep the flywheel in the air. What's the other forces?

And bonus question, my physics book showed me that dθ = dL / L. I can understand this in a trigonometric way with tanθ = opposite / adjacent = dL / L. I can't make the connection between my knowledge in trigonometry and dθ = dL / L. The tanθ != dθ is what's bothering me.
It's not that there is a force keeping it up; it's that the torque from gravity, which is what you'd expect to make it fall over, has the paradoxical effect of making it precess instead.

By the way, you wrote of the gyroscope's angular moment (which is mormally termed angular momentum) and the angular moment (which should be just "moment") of gravity. I.e. you made them sound like they are dimensionally the same, but they are different. Angular momentum is ML2T-1, whereas torque is ML2T-2.
 
Elias Waranoi said:
I know of the force of gravity and the normal force on the pivot connected to the rod connecting to the flywheel but to me that doesn't seem to be enough to keep the flywheel in the air.
Normal force cancels gravity, so there is a force equilibrium. No other forces are needed. The video below might help you.

 
A.T. said:
Normal force cancels gravity, so there is a force equilibrium. No other forces are needed.
So if there is force equilibrium does that mean that the normal force from the pivot is the same size as the force from gravity?
 
Elias Waranoi said:
So if there is force equilibrium does that mean that the normal force from the pivot is the same size as the force from gravity?
The vertical forces must be equal but opposite if there is no vertical acceleration of the center of mass. Since the center of mass moves slowly in circles, the pivot must also provide a small horizontal centripetal force.
 
A.T. said:
Normal force cancels gravity, so there is a force equilibrium. No other forces are needed
True, but I interpreted the question as asking what counters the torque, which would make a pencil, e.g., fall over.
@Elias Waranoi , which were you asking? Maybe it was both.
 
I was asking about force equilibrium. But I appreciate all the responses I get!
 
Elias Waranoi said:
I was asking about force equilibrium. But I appreciate all the responses I get!
The video I posted explains the issue in terms of linear forces and accelerations, which are more intuitive to most people, than torque and angular momentum.
 

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