Half Life / Alpha Decay Question - No IDea

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SUMMARY

The discussion focuses on calculating the age of a space rock containing 3.20 g of 14762Sm and 0.110 g of 14360Nd, where 14762Sm undergoes alpha decay to 14360Nd with a half-life of 1.06 x 1011 years. The solution approach involves applying the decay formula, assuming the initial sample was entirely composed of samarium, while considering the negligible mass loss due to the minor fraction of neodymium present. This method allows for an accurate estimation of the rock's age based on the current proportions of the isotopes.

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Half Life / Alpha Decay Question -- No IDea

Homework Statement



A space rock contains 3.20 g of 147 62 Sm and 0.110 g of 143 60 Nd. 147 62 Sm alpha decays to 143 60 Nd with a half-life of 1.06 1011 yr. If the rock originally contained no , how old is it?

Homework Equations



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The Attempt at a Solution



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If you presume that it was all samarium with no neodymium, then all you need to do is apply the decay formula to the original sample as though all the mass was samarium. (Now it's true that the alpha particles emitted represent a loss of mass, but I'd think since the neodymium is a minor fraction of the samarium you can ignore the loss.)
 

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