- #1

Karajovic

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## Homework Statement

A hang-glider, diving at an angle of 57.0

^{o}with the vertical, drops a water balloon at an altitude of 680.0 m. The water balloon hits the ground 5.20 s after being released.

a. What was the velocity of the hang-glider?

## Homework Equations

## The Attempt at a Solution

we know that the initial speed of the water balloon is the speed of the hang-glider... so:

∆y = vi(∆t)sinx - 1/2g∆t^2

680 = vi(5.2)sin57 - 1/2(-9.81)(5.2)^2

vi = 186 m/s

but my textbook says the answer is 193 m/s.

Is the book wrong? or am I wrong?

thanks!