How Fast Are Water Balloons Traveling When They Pass a Window?

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Homework Help Overview

The discussion revolves around the motion of water balloons falling past a window, specifically focusing on calculating their speed as they pass the window and determining the height from which they were released. The subject area includes kinematics and equations of motion under gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of kinematic equations to find the speed of the balloons and question the assumptions regarding initial and final velocities. There is discussion about the correct application of equations and the impact of air resistance on the balloons' motion.

Discussion Status

Some participants have successfully arrived at a solution for Part A, while others are still clarifying their understanding of the equations involved. There is acknowledgment of the correct approach being used, and guidance has been offered regarding the interpretation of final velocity.

Contextual Notes

Participants are working under the constraints of a homework assignment, which includes specific requirements for expressing answers and the need to clarify any misunderstandings about the physics concepts involved.

Wanting to Learn

Homework Statement


Roger sees water balloons fall past his window. He notices that each balloon strikes the sidewalk 0.83 s after passing his window. Roger's room is on the third floor, 15 m above the sidewalk.
Part A:
How fast are the balloons traveling when they pass Roger's window? (express to 3sig figs with units)
Part B:
Assuming the balloons are being released from rest, from what floor are they being released? Each floor of the dorm is 5.0 m high. (Express answer as integer. Thus the balloons are coming from the floor number _.)

Homework Equations


d = .5(vf + v0)t

vf = 0m/s
v0 = ? m/s
t = 0.83s
d = 15m

The Attempt at a Solution


I plugged in:
15 = .5(0 + v)*0.83
15 = 0.415v
v = 36.14...
I assume units are m/s

When I put 36.1 m/s as the answer (homework is online) it said my answer is incorrect. Where did I do wrong with it?
(I will attempt part B once I have the correct answer for part A.)

Thank you in advance for helping.
 
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Wanting to Learn said:
vf = 0m/s
Is this the final velocity of the balloon just before striking the ground?
 
TSny said:
Is this the final velocity of the balloon just before striking the ground?
Maybe not? I would think that the water balloon keeps getting faster, at least until a certain speed, as it falls, and velocity is 0 when it has hit the ground. Perhaps I need to not use that and use a different equation? (In class we were given a list of equations for accelerating objects but I'm not always sure which one to use.)
 
These are the equations we were given:
Equations for Accelerating Objects.JPG

The right column lists the variables used.
 
Wanting to Learn said:
Maybe not? I would think that the water balloon keeps getting faster, at least until a certain speed, as it falls, and velocity is 0 when it has hit the ground. Perhaps I need to not use that and use a different equation? (In class we were given a list of equations for accelerating objects but I'm not always sure which one to use.)
I think you can safely neglect air resistance, so the balloons will be speeding up the entire time.

As I like to ask my students, "Imagine you are the ground. Would you say the balloons were going 0 m/s when they hit you?"
 
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Okay, so should I try using this equation?
d = v0t + .5at2
so
15 = 0.83v + .5*9.8*0.832
4.4436... = 0.83v
v = 3.6882...

EDIT: 3.69 m/s is not the correct answer, I'm still not sure what I've been doing wrong or if I need to use a different equation
 
I've gotten the correct answer to Part A, turns out I had the correct equation though perhaps typed something incorrectly in the calculator. The answer to Part A is 14.0m/s. I will attempt part B later and post again if I get it or need help.
 
Wanting to Learn said:
I've gotten the correct answer to Part A, turns out I had the correct equation though perhaps typed something incorrectly in the calculator. The answer to Part A is 14.0m/s. I will attempt part B later and post again if I get it or need help.
OK. Your work for part A looks good.
 
Thank you, I did manage to get Part B
 

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