Where did the water balloon fall?

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Medgirl314
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Homework Statement


A boy is on top of a 12 m tall building. He throws a water balloon horizontally, releasing it at a height of 1 m above the top of the building. The water balloon is thrown at 30 mi/h and is aimed at the balconies of an apartment building across the street, 18 m away horizontally. If each story of the apartment building is 3 m high, which balcony gets hit by the water balloon, 1st, 2nd,3rd or 4th floor?

Homework Equations


t=x/v
y=y0+v0t1/2 a(t^2)

The Attempt at a Solution



I attempted to convert the mi/h to m/s and got 80.3 m/s. I used t=x/v to get my time:

t=x/v
t=18/80.3
t=0.22 s

The time seems reasonable enough.

Then I tried using y=y0+v0t+1/2 a(t^2) to find how far down the balloon fell.

y=y0+v0t+1/2a(t^2)
1/2 a(t^2)
y=0+0+1/2 a(t^2)
y=1/2a(t^2)
y=1/2(9.8)(0.22^2)
y=1/2(9.8)(0.0484)
y=0.24 m

Something seems off, but I can't place it. If this answer is right, does that mean it will land on the 4th(top) floor of the building?

Thanks! :smile:
 
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Hm, I thought so. 30 mi=48280.3 m. OH, I see. I calculated to m/min. I need to divide by 60 again, correct? So 1.3 m/s.
 
I didn't think about it that way. Hmm. Okay, so 30 mi/h=48280.3 m/h. Line up the unit conversion so that the hours cancel out. 48280/3600 s=13 m/s. That seems right, finally.
 
Is the time right?
 
I'm getting 9.3 meters, which would put it at the second (next to bottom) floor. Feel free to confirm or correct the answer! :)
 
13.4 m/s hits in 1.34s after dropping 8.8m (from 13m start).
avoid round-offs (especially for things that get squared, like t here), by using the value in the calculator display register.
 
Ah, I see. I used 1.38 seconds. Now I'm getting 8.8 as well. So this should put the balloon at the third (from bottom) floor, correct?

Thanks again!
 
This post is only here because I couldn't delete it.
 
Last edited:
4.2 m. Correct, I don't think I'm thinking about the diagram correctly. It would actually be the second floor, right?