1. The problem statement, all variables and given/known data A boy is on top of a 12 m tall building. He throws a water balloon horizontally, releasing it at a height of 1 m above the top of the building. The water balloon is thrown at 30 mi/h and is aimed at the balconies of an apartment building across the street, 18 m away horizontally. If each story of the apartment building is 3 m high, which balcony gets hit by the water balloon, 1st, 2nd,3rd or 4th floor? 2. Relevant equations t=x/v y=y0+v0t1/2 a(t^2) 3. The attempt at a solution I attempted to convert the mi/h to m/s and got 80.3 m/s. I used t=x/v to get my time: t=x/v t=18/80.3 t=0.22 s The time seems reasonable enough. Then I tried using y=y0+v0t+1/2 a(t^2) to find how far down the balloon fell. y=y0+v0t+1/2a(t^2) 1/2 a(t^2) y=0+0+1/2 a(t^2) y=1/2a(t^2) y=1/2(9.8)(0.22^2) y=1/2(9.8)(0.0484) y=0.24 m Something seems off, but I can't place it. If this answer is right, does that mean it will land on the 4th(top) floor of the building? Thanks!