Hard Thermo Question: Find U, S, T For Part B & C

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SUMMARY

The discussion focuses on solving thermodynamic problems related to calculating internal energy (U), entropy (S), and temperature (T) for parts B and C of a question derived from Reif's textbook, as referenced in Schroeder's book. The user successfully approached part B by deriving the multiplicity function, \(\Omega(N,n) = \binom{N}{N-n} = \frac{N!}{n!(N-n)!}\), and utilized the relationship between temperature and multiplicity, \(\frac{1}{kT} = \frac{\partial \Omega(N,n)}{\partial E}\). However, the user struggles with part C, particularly in differentiating factorials and applying the Stirling approximation effectively.

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mewmew
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Well, it's hard to me at least :frown:
http://img169.imageshack.us/img169/206/questionzg0.png
We are using Schroeders book and this problem was given to us from I assume the book by Reif. We haven't seem to have gotten far enough along in Schroeders book to have gone over this though.

I can do part A, but part B and C I am clueless on. I know that T = partial derivative of U/S but it doesn't seem to be helping me very much. Thanks in advance for any pointers.
 
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Ok, I found B more or less, by taking n=E/e. My equation for T looks pretty nasty because my multiplicity from part A was relatively nasty. I am still pretty much completely stuck on how to do C though.
 
What do you get for A? I get

\Omega(N,n)=\binom{N}{N-n}=\frac{N!}{n!(N-n)!}

(the number of ways to pick the position of the N-n atomes that are not in an interstititiisal position.

Temperature is \frac{1}{kT}=\frac{\partial \Omega(N,n)}{\partial E}.

I guess you said, n=n(E)=E/\epsilon, so then

\frac{\partial \Omega(N,n)}{\partial E}=\frac{\partial \Omega(N,n)}{\partial n}\frac{\partial n}{\partial E}= \frac{\partial \Omega(N,n)}{\partial n}\frac{1}{\epsilon}

But do you know how to take the derivative of a factorial?
 
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Sorry, I Should have been more specific. I took a Sterling approximation of the factorials of the form Ln(x!)= x Ln(x) - x, expanded each term, substituted in n = E/epsilon and differentiated. This was messy though and I am not sure the desired method.
 

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