Harmonic Oscillator - Normalization

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SUMMARY

The discussion focuses on normalizing the first excited state of a harmonic oscillator, specifically addressing the integral calculation of the wave function. The integral in question is defined as 1 = |A_1|^2(iω√(2m)) ∫_{-∞}^{∞} x exp(-mωx²/2ħ) dx. The challenge arises from the integral resulting in zero due to the odd function property of x, leading to confusion among participants regarding the normalization process.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically harmonic oscillators.
  • Familiarity with wave functions and their normalization.
  • Knowledge of integrals involving exponential functions.
  • Basic grasp of complex numbers and their applications in quantum mechanics.
NEXT STEPS
  • Study the normalization of wave functions in quantum mechanics.
  • Learn about the properties of odd and even functions in integrals.
  • Explore techniques for evaluating integrals involving exponential functions.
  • Review the mathematical formulation of the harmonic oscillator in quantum mechanics.
USEFUL FOR

Students of quantum mechanics, physicists working with harmonic oscillators, and anyone involved in wave function normalization processes.

cscott
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Homework Statement



Trying to normalize the first excited state. I have,

[tex]1 = |A_1|^2(i\omega\sqrt{2m}) \int_{-\inf}^{\inf} x \exp(-m\omega x^2/2\hbar)[/tex]

How do I do the integral so I don't get zero since it's an odd funciton?
 
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By calculating [itex]\int \psi^*(x)\psi(x)dx[/itex].
 
Cyosis said:
By calculating [itex]\int \psi^*(x)\psi(x)dx[/itex].

Damn... my head isn't on straight today. Let me get back to you on this. Thanks. :P
 

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