Harmonic oscillator outside classically allowed region

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SUMMARY

The discussion centers on calculating the probability of finding a particle outside the classically allowed region in the ground state of a harmonic oscillator. The classically allowed energy is defined by the equation E=(1/2)mω²a², where 'a' is the amplitude. The wave function is given by ψ(x)=(mω/πħ)^(1/4)(2ⁿn!)^(-1/2)H(zeta)e^(-zeta²/2), with n=0 for the ground state. The integral of e^(-a*x²) from 0 to the classical energy cannot be solved analytically and requires numerical methods, such as using the error function or computational tools like Maple or Mathematica.

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yukikokami
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the problem is as follows: in the ground state of the harmonic oscillator what is the probability of finding the particle outside the classically allowed region. where the classically allowed nrg is given by E=(1/2)m*omega^2*a^2 (where a is the amplitude).

were given that psi(x)=(m*omega/pi*h-bar)^(1/4)*(2^n*n!)^(-1/2)*H(zeta)*e^(-zeta^2/2)
where H(zeta) depends on n, but for this problem n=0

so i figured that if the probability of this from 0 to infinity (which is 1/2) then subtract the probability from 0 to the classical nrg, then the remainer should be the probability of finding it outside the said classical region. right?

but that leads to the problem of finding the integral of e^(-a*x^2) from 0 to classical nrg... and this doesn't seem possible... is it?

cheers!
 
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yukikokami said:
the problem is as follows: in the ground state of the harmonic oscillator what is the probability of finding the particle outside the classically allowed region. where the classically allowed nrg is given by E=(1/2)m*omega^2*a^2 (where a is the amplitude).

were given that psi(x)=(m*omega/pi*h-bar)^(1/4)*(2^n*n!)^(-1/2)*H(zeta)*e^(-zeta^2/2)
where H(zeta) depends on n, but for this problem n=0

so i figured that if the probability of this from 0 to infinity (which is 1/2) then subtract the probability from 0 to the classical nrg, then the remainer should be the probability of finding it outside the said classical region. right?

but that leads to the problem of finding the integral of e^(-a*x^2) from 0 to classical nrg... and this doesn't seem possible... is it?

cheers!

It's not possible analytically, it must be done numerically. Look up a table of the "error function" (be careful, depending on the convention used in the book you pick up, you might have to do some work to convert th eresult of the table into the form you need) or use Maple/Mathematica.

Patrick
 

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