Having a hard time solving last part

  • Thread starter mikenash
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  • #1
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You throw a ball toward a wall at speed 24.0 m/s and at angle θ0 = 43.0° above the horizontal (Fig. 4-35). The wall is distance d = 16.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall?


(a)Number 10.7 Units m correct
(b)Number 17.5 Units m/s correct ---- cos(43)* 24
(c)Number Units m/s -- can not get --- attempt-- sin(43) *24
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
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You throw a ball toward a wall at speed 24.0 m/s and at angle θ0 = 43.0° above the horizontal (Fig. 4-35). The wall is distance d = 16.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall?


(a)Number 10.7 Units m correct
(b)Number 17.5 Units m/s correct ---- cos(43)* 24
(c)Number Units m/s -- can not get --- attempt-- sin(43) *24
What is your vertical velocity component when it strikes the wall? Remember at the time it strikes the wall it has been slowed by gravity and will no longer be the Initial vertical component. When you figure that, you can add the component vectors to arrive at the result.
 

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