Having a very hard time in my PRECALC CLASS

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SUMMARY

The discussion centers on a precalculus problem involving the factorization of the expression 3(4x+5)^2 (4)(5x+1)^2 + (4x+5)^3 (2) (5x+1)(5). The professor's solution includes the expression 2(4x+5)^2(5x+1)[6(5x+1)+5(4x+5)], where the participant questions the origin of the coefficients 6 and 5. The clarification provided indicates that the coefficient 6 arises from the factorization process, specifically from the multiplication of 3 and 4, and the necessity to maintain equivalence after factoring out a 2.

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DeepSpace9
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Having a very hard time in my PRECALC CLASS.
When they facto problems they start pulling numbers out of numbers that aren't there..
Example..

3(4x+5)^2 (4)(5x+1)^2 + (4x+5)^3 (2) (5x+1)(5)

Professor said this was the answer.

a) 2(4x+5)^2(5x+1)[6(5x+1)+5(4x+5)]
=
b) 2(4x+5)^2(5x+1)[50x+31] (After combining like terms)

My questions is

Where I labeled a) where did she get the 6 from and the 5 from?
I can see she got the 5 from the original problem, but I thought if she factored out a 2 as a GCF the 5 would be reduced to a smaller number, and the 6 comes out of no where.. HELP
 
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Thanks for the help guys.
 


Hey DeepSpace9.

Recall that 3*4 = 12 = 6*2 and 5*2 = 10 = 5*2 [Look at the factorization again carefully with the hint mentioned]
 
So the 6 comes from the fact that (3)(4) = 12 and since I factor out a (2) I would need a (6) to = 12 again? I didn't think we could use a 6 since it was not in the original problem.
 
Yes that's pretty much it.
 

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