MHB Having difficulty finding the elements in each set

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The discussion focuses on set operations involving the universal set U and subsets A, B, C, and D. Participants clarify the meanings of intersection, difference, and union in set theory, providing examples with specific elements. For instance, C intersect D results in the set {2}, while C minus D yields {1, 5, 6}. The conversation emphasizes understanding these operations to solve the given problems effectively. Overall, the thread aims to assist users in mastering set operations and overcoming difficulties in identifying elements within the specified sets.
chelseajjc95
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Find the elements in each set given that:

U={1,2,3,4,5,6,7}
A={1,3,5,7}
B={2,4,6}
C={1,2,5,6}
D={2,3,4}

A) C intersect D B) C-D C) (A union B) union C D) (C union A)' -D
 
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Where do the difficulties lie? Do you know what X intersect Y means, for example?
 
[math]X\cap Y[/math], "X intersect Y", means "all things that are in both set X and set Y". Here you are given that C= {1, 2, 5, 6} and D= {2, 3, 4}. "1" is in C but not in D so is NOT in [math]C\cap D[/math]. "2" is in both C and D so is in [math]C\cap D[/math]. "5" is in C but not in D so in NOT in [math]C\cap D[/math]. "6" is in C but not in D so NOT in [math]C\cap D[/math]. We don't need to consider either "3" or "4" since they are not in C. [math]C\cap D= \{1, 2, 5, 6\}\cap \{2, 3, 4\}= \{2\}[/math].

"X- Y" is defined as "all things that are in X but NOT in Y". "1", "5", and "6" are in C but not in D so [math]C- D= \{1, 5, 6\}[/math].

Now try the others. How are "X union Y" and "X' " defined?
 
There is a nice little variation of the problem. The host says, after you have chosen the door, that you can change your guess, but to sweeten the deal, he says you can choose the two other doors, if you wish. This proposition is a no brainer, however before you are quick enough to accept it, the host opens one of the two doors and it is empty. In this version you really want to change your pick, but at the same time ask yourself is the host impartial and does that change anything. The host...

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