Having Trouble Calculating Moments in Physics?

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Homework Help Overview

The discussion revolves around calculating the weight of a workman using principles of moments in a physics context. The original poster expresses difficulty in understanding the problem and references an answer sheet that provided partial clarity but left them confused about certain values and their derivations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the weight using given distances and moments but questions the inclusion of additional distances (R and S) in their calculations. Some participants suggest solving the problem symbolically before substituting numbers and emphasize the importance of equilibrium conditions in the analysis.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the setup of equations related to equilibrium. Some guidance has been offered on the importance of understanding torque and moments, but there is no explicit consensus on the correct approach or solution yet.

Contextual Notes

There is mention of ambiguity in the relevant equations and the need for clarity on the moments being discussed. The original poster also notes confusion regarding specific values mentioned in the answer sheet and their derivation.

Taylor_1989
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Homework Statement


I am having problem calculating this question. I even looked at the answer sheet and worked back, which gave me some luck, but still do not fully grasp the question.(i) Calculate the weight W of the workman.


Homework Equations


moment clockwise = moment anticlockwise


The Attempt at a Solution


My attempt pre look at question: I did 0.20-0.03= 0.17, 0.20+0.03= 0.23 so far so good.
I the did 0.20+0.50=0.70 so middle Q which then gave me 0.67 and 0.73. I then took the W*0.17=160*0.73.

But when I looked at the answer I got the first part right but the second part wrong. Do I have to include R and S into the equation? I would appreciate the help if possible.

Also here is what the answer says: W × 0.17/0.20/0.23 = 160 × 0.72/0.75/0.78
W × 0.17 = 160 × 0.78 or 600 N
730/734 N

I really can't see where the 0.72 ect come from unless you included distance from R S but the weight is in the middle.
 

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The first thing to do, for this and all problems, is to solve it symbolically; forget there are numbers until the very last step. You'll never learn the physics if you plug in numbers from the beginning.

Second, your "relevant equation" is not only ambiguous (what moment are you talking about), it is wrong. The system is in equilibrium, so the net force is zero and the net torque is also zero. That is your starting point. Write down those equations, then solve for W.
 
tms said:
The first thing to do, for this and all problems, is to solve it symbolically; forget there are numbers until the very last step. You'll never learn the physics if you plug in numbers from the beginning.

Second, your "relevant equation" is not only ambiguous (what moment are you talking about), it is wrong. The system is in equilibrium, so the net force is zero and the net torque is also zero. That is your starting point. Write down those equations, then solve for W.

could you please expand, I really can't see where you are coming from. I have looked in my study books and the point me in the directions of levers and moments.
 
The torque of the man plus his segment of the board and the torque of the rest of the board must be equal. Recall that \mathbf\tau = \mathbf{r} \times \mathbf{F}. Since the angles of both torques are 90 degrees, this reduces to \tau = rF.
 

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