How Do You Solve Complex Torque Problems in Physics?

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SUMMARY

This discussion focuses on solving complex torque problems in physics, specifically addressing three distinct scenarios involving torque calculations. The first problem involves a uniform plank of length 5.9 m and weight 216 N, where the tipping point is determined by a person weighing 447 N walking on the overhanging part. The second problem calculates the horizontal force exerted by a person's flexor muscle on their forearm, given a force of 174 N. The third problem requires finding the moment of inertia of a three-legged stool configuration, consisting of a solid circular disk and three rods, with a total mass of 1.2 kg and radius of 0.12 m.

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SJustice21
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The 1st Problem is:
A uniform plank of length 5.9 m and weight 216 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 447 N walk on the overhanging part of the plank before it just begins to tip?
________m


2nd is:
A person exerts a horizontal force of F = 174 N in the test apparatus shown in the drawing. (h = 0.33 m.) Find the horizontal force M that his flexor muscle exerts on his forearm.
Magnitude __________N


3rd is(hardest one):
A solid circular disk has a mass of 1.2 kg and a radius of 0.12 m. Each of three identical thin rods has a mass of 0.13 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the drawing). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)____________kg . m2


*Any help will be Appreciated
 
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Where are the drawings?
 
1st
When the person is at max distance and at the verge of tipping the normal reaction at the support on other side is just zero, balances the torque due to weight of the plank and that of the person.

3rd
The hint is given but I guess still you have taken moment of inertia of the rods wrongly

it will be simply 3 x mR^2
 

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