Hawking radiation temperature -- observer dependent?

[bcrelling]

Black holes are claimed to radiate at a temperature corresponding to the hawking radiation. But who is measuring the temperature? If the radiation is measured from far away the red shift will indicate a lower temperature won't it?

Is the temperature given by the formula as measured from a hypothetical probe suspended at the event horizon? If so, will the proper acceleration of the probe experience unruh radiation too, or in this case would they be one and the same thing(unruh and hawking radiation)?

 

[Doug Huffman]

There is an absolute temperature scale.

 

[Demystifier]

Hawking temperature is the temperature measured by an observer far away from the horizon. An observer close to the horizon will see a higher temperature.

 

[bcrelling]

Hawking temperature is the temperature measured by an observer far away from the horizon. An observer close to the horizon will see a higher temperature.

Would the increased temperature as measured by an observer at the horizon be definable?

Is this where the idea of the black hole fire wall comes from?

 

[Demystifier]

Would the increased temperature as measured by an observer at the horizon be definable?

It would be infinite, but infinity can be replaced by a large finite number by appropriate regularization.

Is this where the idea of the black hole fire wall comes from?

It is closely related to it.