Head-on Proton Collision: Finding Speed

Click For Summary
SUMMARY

The discussion centers on calculating the initial speeds of two protons in a head-on collision, where one proton has twice the speed of the other. The closest approach during the collision is noted as 3.0 x 1014 m. Participants emphasize using the conservation of energy principle, represented by the equation {1/2} m1 v12 + {1/2} m2 v22 - {k q1 q2 / r}, to solve for the unknowns: mass, velocity, and charge. The challenge lies in managing three unknowns simultaneously.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with the equations of motion for particles
  • Basic knowledge of electrostatic forces and Coulomb's law
  • Ability to manipulate algebraic equations with multiple variables
NEXT STEPS
  • Study the conservation of energy in particle collisions
  • Learn how to apply Coulomb's law in collision scenarios
  • Explore methods for solving systems of equations with multiple unknowns
  • Investigate the dynamics of particle accelerators and head-on collisions
USEFUL FOR

Physics students, researchers in particle physics, and anyone interested in understanding the dynamics of proton collisions and energy conservation principles.

kevykevy
Messages
25
Reaction score
0
Question - Two protons, separated by a large distance, are fired directly at each other. The closest approach in this head-on collision is 3.0 x 10^14 m. One proton starts with two times the speed of the other. Assuming there is no delection from the original path, determine the initial speed of each proton.

Solution - I read through my notes and textbook but I couldn't find any way to connect speed with this question. Is there any specific equations to use?
 
Physics news on Phys.org
kevykevy said:
Question - Two protons, separated by a large distance, are fired directly at each other. The closest approach in this head-on collision is 3.0 x 10^14 m. One proton starts with two times the speed of the other. Assuming there is no delection from the original path, determine the initial speed of each proton.

Solution - I read through my notes and textbook but I couldn't find any way to connect speed with this question. Is there any specific equations to use?
Conservation of energy.

the total energy is {1 \over 2} m_1 v_1^2 + {1 \over 2} m_2 v_2^2 - {k q_1 q_2 \over r} and it is conserved.
 
So, since I don't know what the mass is or the speed, would I split the question up into two parts, the first being at collision so I can solve for mass since speed is zero. Then I can use the law of conservation of energy to find velocity at start?
 
Actually, how would I solve that if there is 3 unknowns: mass, velocity, and charge?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K