1. The problem statement, all variables and given/known data A 75.0g ice cube at 0 C is placed in 825g of water at 25 C. Find final temp. 2. Relevant equations Well none really, this should be simple plugging into to heat equations. 3. The attempt at a solution Heat required to melt ice = (0.075kg)(3.33*10^5) = 24975 J Heat required to melt ice + Heat required to raise temp of melted ice = heat released from dropping temp of water 24975 + (0.075kg)(4186J/kg C)(Tf) = (0.825)(4186J/kg C)(Tf - 25) Rearrange the equation: Tf ends up being 35.4, which is impossible. What am I doing wrong?