Heat exchanger consisting of Coaxial Cables

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SUMMARY

The discussion focuses on the calculation of heat transfer in a heat exchanger consisting of two co-axial tubes with square cross-sections. The inner tube carries liquid 1 at temperature T10, while liquid 2 at temperature T20 flows through the space between the tubes. The derived temperature difference, ΔT(x) = (T10 - T20)exp(-αx), is established where α = (4a/s)κ[(m1C1)⁻¹ – (m2C2)⁻¹]. Key assumptions include negligible transverse temperature gradients and longitudinal heat conduction. Participants discuss the mathematical modeling of heat flow and the relationship between temperature changes and flow rates.

PREREQUISITES
  • Understanding of heat transfer principles, specifically conduction.
  • Familiarity with differential equations and their applications in thermal systems.
  • Knowledge of specific heat capacities (C1 and C2) and their role in thermal dynamics.
  • Basic calculus, particularly integration techniques for solving differential equations.
NEXT STEPS
  • Study the derivation of heat transfer equations in co-axial heat exchangers.
  • Learn about the impact of flow rates (m1 and m2) on temperature profiles in thermal systems.
  • Explore the concept of thermal resistance and its analogy to electrical circuits in heat exchangers.
  • Investigate numerical methods for solving differential equations related to heat transfer.
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Students and professionals in mechanical engineering, thermal engineering, and anyone involved in the design and analysis of heat exchangers and thermal systems.

  • #31
The solution to dy/dx = ky is y = Ae^kx
so your solution should by T2 - T1 = Ae^kx, k = (constant expression with k4a's on top)
Let x = 0 to see what A should be.

Missing the closing bracket on the constants (after the C1). Instead of (T2 - T1)dx, you should have just x. Missing the constant before e.

Compare with the given answer in your first post. Looks like the answer has T1 - T2 instead of T2 - T1; probably doesn't matter.
 
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  • #32
okay, so differnce is that they should be other way around...

(T_1 - T_2) = Ae^{(\frac{\kappa 4a}{s m_1 C_1} - \frac{\kappa 4a}{sm_2C_2}) (T_2 - T_1))dx}

Now this is looking similar to the required equation, except T1 - T2 is on the other side, where A is, and instead on the left is delta T. Also, there exponential is:

(4a/s)\kappa [(m_1C_1) -1 – (m_2C_2) - 1]x
 

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