- #1

Saitama

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## Homework Statement

(see attachment)

## Homework Equations

## The Attempt at a Solution

When the switch is open, the charges on the plates will rearrange and the final charges would be as shown in attachment 2. The energy stored due to the electric field between the plates (sorry if I said it incorrectly) is ##U=\frac{1}{2}ε_o E^2 \cdot (Ad)##, where E is the electric field between the plates. Solving I get, ##U=\frac{q^2d}{2Aε_o}##. I don't know how to proceed from here.

Any help is appreciated. Thanks!