Heat transfer by radiation between two plates

In summary, the problem discusses two large plates held at different temperatures in a vacuum. The solution, using the Stefan-Boltzmann Law, is 368[w/m2] if the emission is of a black body. However, the emissivities of the surfaces do not count in this formula, which may seem paradoxical. The sign of the energy transfer cannot change, but the overall magnitude of exchanged energy can go down. In an insulated chamber, the emission of a body and the emission of the walls is not considered to be of a black body, as the energy exchange rate with the objects depends on their emissivity.
  • #1
Karol
1,380
22

Homework Statement


Two large plates are parallel and close to each other, vacuum is between them. they are held at 2000K and 3000K.
What is the energy transfer rate between them.

Homework Equations


The energy emission rate per unit area-the Stefan-Boltzmann Law: $$R=\varepsilon\sigma T^4$$
##\varepsilon## is the emissivity of the surface
##\sigma=5.672E-8[w/sec]##

The Attempt at a Solution


The solution is 368[w/m2], it's the answer if the emission is of a black body:
##1\cdot 5.672E-8\cdot\left(300^4-200^4\right)=368##
But why don't the emissivities of the surfaces count? what if one surface emits more or less than the other?
In the Stefan-Boltzman formula the outer temperature exists, not the nature of the surrounding surfaces.
I guess it has something to do with the fact that the rest of the radiation, which isn't absorbed, is reflected and comes into account
 
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  • #2
Karol said:
But why don't the emissivities of the surfaces count?
They do count, and the problem statement should specify that ideal black bodies are meant. The sign of the energy transfer cannot change, but the overall magnitude of exchanged energy can go down.
 
  • #3
mfb said:
The sign of the energy transfer cannot change, but the overall magnitude of exchanged energy can go down.
What do you mean by "sign"?
 
  • #4
Karol said:
What do you mean by "sign"?
Meaning which way the net flow goes.
If one body has lower emissivity than that of a black body then it both emits less and absorbs less. Different emissivities cannot result in the net flow being from the cooler to the hotter.
 
  • #5
Of course not from the cooler to the hotter, but different emissivities must mean smaller energy flow. it doesn't matter which plate's emissivity is smaller, right?
 
  • #6
Karol said:
Of course not from the cooler to the hotter
You say 'of course', but if the emissivity affected only the emission rate and not the absorption rate then you could have the paradoxical situation that a hot body with low emissivity could gain energy from a cooler body.
but different emissivities must mean smaller energy flow. it doesn't matter which plate's emissivity is smaller, right?
It's not that they're different, just that one, the other or both are lower than a black body's.
 
  • #7
Thanks
 
  • #8
Why in an insulated chamber the emission of a body and the emission of the walls is black body? why don't we take into account the emissivity of the walls?
 
  • #9
Karol said:
Why in an insulated chamber the emission of a body and the emission of the walls is black body?
It is not.
The energy density in the cavity does not depend on the emissivity, but the energy exchange rate with the objects does.
 
  • #10
mfb said:
The energy density in the cavity does not depend on the emissivity
Why? if the walls inside emit low radiation, because of small emissivity, then the energy density in the opening will also be low, no?
 
  • #11
Karol said:
Why? if the walls inside emit low radiation, because of small emissivity, then the energy density in the opening will also be low, no?
No. This is exactly the same point as for the two bodies at different temperatures. If the emissivity is low then the absorption from the cavity is correspondingly low. Equilibrium will still be achieved when the energy density corresponds to the temperature of the enclosure.
 

1. What is heat transfer by radiation?

Heat transfer by radiation is the process of transferring thermal energy between objects without the need for a conducting medium. It occurs through electromagnetic waves, such as infrared radiation, that are emitted by one object and absorbed by another, resulting in a change in temperature.

2. How does heat transfer by radiation occur between two plates?

When two plates are placed close to each other, they will both emit and absorb thermal radiation. The rate of heat transfer will depend on the temperature difference between the plates and the surface properties, such as reflectivity and emissivity, of the materials.

3. What is the difference between conduction and radiation heat transfer?

Conduction is the transfer of heat through direct contact between two objects, without any movement of particles. Radiation, on the other hand, does not require contact and can occur in a vacuum. It is also the only method of heat transfer that can occur through empty space.

4. How does the temperature of the plates affect heat transfer by radiation?

The temperature difference between the two plates will determine the rate of heat transfer by radiation. The greater the temperature difference, the faster the transfer of thermal energy. This is because objects with higher temperatures emit more radiation.

5. What factors affect the rate of heat transfer by radiation between two plates?

The rate of heat transfer by radiation is affected by several factors, including the temperature difference between the plates, the surface properties of the materials, the distance between the plates, and the presence of any obstructing objects or mediums. Additionally, the type of radiation being emitted, such as infrared or visible light, can also impact the rate of heat transfer.

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