Heat Transfer Equation: Balance of Energy Explained

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SUMMARY

The discussion centers on the Heat Transfer Equation, specifically the steady-state condition represented by the equation d²T/dx² + qgen = qstored. This equation incorporates the second derivative of temperature, which accounts for the net heat accumulation in a segment of a rod. In contrast, the equation qconv + qcond + qgen = qstored balances energy through convection and conduction, utilizing first derivatives. The distinction between these equations is critical for understanding heat transfer dynamics in one-dimensional systems.

PREREQUISITES
  • Understanding of the Heat Transfer Equation
  • Familiarity with concepts of steady-state heat transfer
  • Knowledge of first and second derivatives in calculus
  • Basic principles of conduction and convection
NEXT STEPS
  • Study the derivation of the Heat Transfer Equation in one-dimensional systems
  • Explore the principles of thermal conduction using Fourier's Law
  • Learn about the role of boundary conditions in heat transfer problems
  • Investigate numerical methods for solving heat transfer equations
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Students and professionals in mechanical engineering, thermal engineering, and physics who are seeking to deepen their understanding of heat transfer principles and equations.

Tekneek
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In terms of Heat equation it is d2T/dx2 + qgen = qstored assuming steady state, heat flows in one direction.

But I have seen examples where energy is balanced in terms of qconv + qcond + qgen= qstored

Why is the first equation just not the first derivative of Temperature with respected to x?

Why does one equation have second derivative while the other has just one (for example: qcond = -k(dT/dx). For instance, when u calculate heat generated wouldn't the answer be different? I am confused.
 
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Tekneek said:
In terms of Heat equation it is d2T/dx2 + qgen = qstored assuming steady state, heat flows in one direction.

But I have seen examples where energy is balanced in terms of qconv + qcond + qgen= qstored

Why is the first equation just not the first derivative of Temperature with respected to x?

Why does one equation have second derivative while the other has just one (for example: qcond = -k(dT/dx). For instance, when u calculate heat generated wouldn't the answer be different? I am confused.
In the first equation your wrote, the term involving the second derivative of T represents an energy balance on a segment of the rod between x and x + dx. So you have to subtract the heat conducted in at x (involving a first derivative of T) from the heat conducted out at x + dx (also involving a first derivative of T) to get the net heat accumulated between x and x + dx. This leads to the second derivative.

Chet
 

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