Heisenberg Uncertainty Principle

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SUMMARY

The discussion focuses on applying the Heisenberg Uncertainty Principle to a scenario involving a beam of 50 eV electrons passing through a slit of width 6 micrometers. The wavelength of the electrons is calculated to be 1.74 x 10-10 m using the de Broglie relation. The angular spread of the diffraction pattern is determined to be +/- 2.9 x 10-5, leading to an estimated uncertainty in the y-component of momentum of 4.55 x 10-31 kg·m/s. The relationship between the uncertainty in momentum and position is clarified, emphasizing that increased distance to the observation screen results in greater certainty in momentum.

PREREQUISITES
  • Understanding of the Heisenberg Uncertainty Principle
  • Familiarity with wave-particle duality and de Broglie wavelength
  • Knowledge of basic quantum mechanics equations, particularly momentum and energy relations
  • Ability to perform trigonometric calculations related to diffraction patterns
NEXT STEPS
  • Study the derivation and implications of the Heisenberg Uncertainty Principle
  • Learn about diffraction patterns and their mathematical descriptions in quantum mechanics
  • Explore the concept of wave-particle duality in more depth
  • Investigate the relationship between electron energy and wavelength using the de Broglie equation
USEFUL FOR

Students studying quantum mechanics, physicists interested in wave-particle duality, and anyone seeking to understand the implications of the Heisenberg Uncertainty Principle in practical scenarios.

EEWannabe
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Homework Statement


A beam of 50eV electrons travel towards a slit of width 6 micro metres. The diffraction pattern is observed on a screen 2m away.

Use the angular spread of the central diffraction pattern (+/- lambda / slit width) to estimate the uncertainty in the y-component of momentum of an electron.

Use this result and the Heisenberg uncertainty principle to estimate the minimum uncertainty in the y-coordinate of an electron just after it has passed trough the slit. Comment on this result.

Homework Equations


n\lambda = d sin\theta [1]
\lambda = \frac{h}{p} [2]
E = \frac{p^{2}}{2m} [3]

The Attempt at a Solution



Okay, well I first began by using equation 3 combined with equation 2 to work out the wavelength of the electron. This came out as 1.74 * 10^-10 m.

Re-arranging equation 1 i get sin\theta = +/- lambda/d = +/- 2.9*10^-5

Now i get to the crux of my problem

QM.jpg


It asks to work out the uncertainty in the y component of the momentum, is the uncertainty in the y position given by what's labelled there in the picture, or is it from the central point to the top of the fringe?

Assuming that it is what I've drawn, that leads me to the uncertainty in momentum being = 4.55*10^-31. Well okay.

However again I'm troubled by the next part, it says using the result of the past bit...I can't see how they relate at all! :(. Also i can't see how the further away the screen gets, the more certain the momentum will become! I'm confused.

Thanks for reading this far !

I appreciate any help you can offer!
 
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any help would be great- this is in for tomorrow :(
 

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