Heisenberg's uncertainty principle, find uncertainty in position

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Glissando
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Homework Statement


Using Heisenberg's uncertainty principle, calculate the uncertainty in the position of a proton moving at a speed of (5.00±0.01) x 10^4 m/s.


Homework Equations


Δx[itex]\geq[/itex] [itex]\frac{h}{4mΔv\pi}[/itex]


The Attempt at a Solution


x[itex]\geq[/itex] (6.626*10^-34)/(4pi(1.6726*10^-24)(5±0.01 * 10^4)

I get how to solve it, I just don't really understand what to do with the ±0.01. I'm assuming it's in meters, so I have to do 0.01/5 and then multiply that by 5*10^4, but I'm supposed to be getting 3*10^-10

Thanks in advance (:
 
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The formula says [itex]\Delta x=\frac{h}{4\pi m\Delta v}[/itex]
What is [itex]\Delta v[/itex]? Is it a relative or an absolute uncertainty?