Heisenberg's Uncertainty Principle using Linear Algebra

  • #1
182
19
I am working through linear algebra from MITs MOOC online courses. One of the question refers to the uncertainty principle. It states:



AB-BA=I can happen for infinite matrices with A

[tex]A=A^{ T }\\ and\\ B=-B^{ T }\\ Then\\ x^{ T }x=x^{ T }ABx-x^{ T }BAx\le 2\parallel Ax\parallel \parallel Bx\parallel[/tex]

My question is how does
[tex]x^{ T }x=x^{ T }ABx-x^{ T }BAx [/tex]?
 
Physics news on Phys.org
  • #2
Like you said:
rpthomps said:
AB-BA=I

Thanks
Bill
 
  • Like
Likes rpthomps
  • #3
bhobba said:
Like you said:


Thanks
Bill

Okay. I should have got that one. :) Okay, now I want to prove the premise AB-BA=I, is there an elegant way of doing that?
 
  • #4
rpthomps said:
Okay. I should have got that one. :) Okay, now I want to prove the premise AB-BA=I, is there an elegant way of doing that?

That is the premise of the theorem except for a multiplicative constant - the I is replaced by iC - C a real constant.

Thanks
Bill
 
  • Like
Likes rpthomps
  • #5
Thanks again I really appreciate your attention.
 

Suggested for: Heisenberg's Uncertainty Principle using Linear Algebra

Replies
10
Views
944
Replies
12
Views
231
Replies
2
Views
656
Replies
2
Views
806
Replies
6
Views
1K
Replies
9
Views
707
Replies
16
Views
732
Replies
2
Views
680
Back
Top