Helicopter Lifting off(Newtons Laws). Help please?

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To determine the upward force a medical helicopter must generate to lift off, the weight of the helicopter (7000 lbs) must be countered by the thrust (T) produced by the propeller. The equation T - w = ma is used, where 'w' is the weight and 'a' is the acceleration. The correct approach involves recognizing that the upward acceleration of 10 ft/s² should not be treated as negative, as it opposes gravity. Thus, the total acceleration is the sum of gravitational acceleration and the desired upward acceleration. The final thrust required is calculated by adjusting for both forces acting in opposite directions.
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Homework Statement


A medical helicopter weighs 7000 lbs. How much upward force must the propeller supply for it to lift off at 10ft/sec(squared)?


Homework Equations



T-w=ma, w=mg

The Attempt at a Solution


Here is what I tried:
T-w=ma.....w=mg---7000=m(32.2)=217.39k
T-7000= 217.39(-10ft/s)
T=4826.1

What am I doing wrong here? Shouldnt the acceleration be a negative value since it is going upward? and what should the actual final answer be?
 
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F = m * a

now, to go up, it must counter both gravitational acceleration, plus add that additional 10 ft/sec acceleration

so "a" = 10 ft/sec + ...
 
I see, thank you.
So technically, the only thing I did wrong was the negative sign.
 
Yeah, because if you're doing T-w then you're saying that 'g' is acting in the negative direction since you're subtracting it from upward force. Since the 10 ft/s are in the opposite direction from g, it can't be negative TOO
 
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