Physics Forces Problem: Helicopter lifting a truck

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SUMMARY

The discussion focuses on calculating the tension in the lifting cable of a military helicopter lifting a 6,000-kg truck with an acceleration of 4 m/s². The correct formula applied is T = mtruck * (g + a), where g is the acceleration due to gravity (9.8 m/s²). The calculated tension is 83,000 N, confirming that the forces acting on the truck include both gravity and the upward tension. The participant also discusses the relationship between the helicopter's mass and the tension, clarifying the dynamics involved in the lifting process.

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  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational force calculation (W = mg)
  • Basic principles of force equilibrium in vertical motion
  • Familiarity with unit conversions and significant figures in physics calculations
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Homework Statement



A large (15,000-kg) military helicopter lifts a 6000-kg truck straight up out of a danger zone with an acceleration of 4 m/s2. Calculate the tension in the lifting cable.

Homework Equations



F = ma
W = mg


The Attempt at a Solution


I believe T = 8.3 * 104N, but I am unsure.
For the truck: ƩFy = -mg + T = mtruck * a = 24000
T = 24000 + mtruckg = 24000 + (6000 * 9.8) = 8.3 * 104N
 
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I think your equation should be

mhelia = T-mtruckg

As I am assuming that the helicopter is now lifting the truck off of the ground.
 
Why would it be mhelia instead of mtrucka? That doesn't make much sense to me.

The forces acting on the truck are gravity and tension, so
ƩFon truck = T - mtruckg = mtrucka
 

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