Helicopter Lifting off(Newtons Laws). Help please?

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Homework Help Overview

The problem involves a medical helicopter's lifting force in relation to Newton's laws of motion, specifically addressing the forces acting on the helicopter as it attempts to lift off with a specified upward acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between thrust, weight, and acceleration, questioning the treatment of acceleration as negative when considering upward motion. There is an exploration of the correct application of Newton's second law in this context.

Discussion Status

Participants are actively engaging with the problem, with some providing insights into the correct interpretation of forces and acceleration. There is recognition of potential errors in sign conventions, but no consensus on a final solution has been reached.

Contextual Notes

There is an ongoing discussion about the assumptions regarding the direction of gravitational force and how it interacts with the upward acceleration of the helicopter. Participants are considering the implications of these assumptions on the calculations being performed.

bob24
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Homework Statement


A medical helicopter weighs 7000 lbs. How much upward force must the propeller supply for it to lift off at 10ft/sec(squared)?


Homework Equations



T-w=ma, w=mg

The Attempt at a Solution


Here is what I tried:
T-w=ma.....w=mg---7000=m(32.2)=217.39k
T-7000= 217.39(-10ft/s)
T=4826.1

What am I doing wrong here? Shouldnt the acceleration be a negative value since it is going upward? and what should the actual final answer be?
 
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F = m * a

now, to go up, it must counter both gravitational acceleration, plus add that additional 10 ft/sec acceleration

so "a" = 10 ft/sec + ...
 
I see, thank you.
So technically, the only thing I did wrong was the negative sign.
 
Yeah, because if you're doing T-w then you're saying that 'g' is acting in the negative direction since you're subtracting it from upward force. Since the 10 ft/s are in the opposite direction from g, it can't be negative TOO
 

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