Hello How to prove the min function is continuous?

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To prove that the function f_{3} = min{f_{1}, f_{2}} is continuous, it is essential to consider the cases where f_{1} and f_{2} are equal and where they differ. The discussion suggests using the gluing lemma for a more structured approach. A quick solution provided is to express min(f, g) as (f + g)/2 - |f - g|/2. This formulation helps in demonstrating the continuity of the minimum function effectively. Understanding these concepts is crucial for tackling such proofs in analysis.
simpleeyelid
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Hello!

Could anybody give me an idea about this proof?

knowing f_{i}:X\rightarrowR i=1,2

to show whether f_{3}=min{f_{1},f_{2}} is continuous!

Thanks in advance,

Regards
 
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Presumably f1 and f2 are continuous themselves? Is this a homework problem? I'll give you a small hint: work on the points where f1(x)=/=f2(x) and f1(x)=f2(x) separately
 
yeah, thanks, a lot, I finally find that it is convenient to construct it using the gluing lemma.
 
quick solution:

min(f, g) = (f+g)/2 - |f-g|/2
 

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