Help Conserv. of Energy Momentum is Driving Me Crazy

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SUMMARY

The problem involves a 100 g granite cube sliding down a 35-degree frictionless ramp and colliding with a 215 g steel cube at rest. To achieve a speed of 200 cm/s for the steel cube post-collision, the granite cube must be released from a specific height. The solution requires applying the conservation of momentum and energy equations, leading to the conclusion that the granite and steel cubes behave as a single unit after the collision. The height can be calculated using the equation s*sin(35) where s is the distance traveled along the ramp.

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  • Understanding of conservation of momentum and energy principles
  • Familiarity with kinematic equations, specifically v^2 = u^2 + 2as
  • Knowledge of basic trigonometry, particularly sine functions
  • Ability to set up and solve systems of equations
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  • Study the application of conservation of momentum in collisions
  • Learn how to derive height from ramp distance using trigonometric functions
  • Explore kinematic equations in detail, focusing on their application in physics problems
  • Practice solving systems of equations with multiple variables in physics contexts
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Homework Statement



A 100 g granite cube slides down a 35 degree frictionless ramp. At the bottom, just as it exits onto a horizontal table, it collides with a 215 g steel cube at rest.
How high above the table should the granite cube be released to give the steel cube a speed of 200 cm/s?

Homework Equations



Conservation of momentum and energy equations. I don't know if there are more?


The Attempt at a Solution



For momentum: .1v1=.1v1_f+.215v2_f

For energy: .1(9.81)h=.5(.1)v1_f^2+.5(.215)v2_f^2

I know I'm supposed to solve a system of equations, but I have way too many variables right now. What am I doing wrong? What should I do next?
 
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Have you done some sketches? Can you see a way of breaking this problem down into smaller parts?
 
Hi

Ill tell you the path to solve this. it seems that there is a lack of given data. to overcome that you have to do the following assumption.

after the collision the granite cube and the steel cube behaves as a single unit.

from the equations of conservation of momentum find the velocity of the granite cube before the collision.

then apply v^2=u^2+2as along the ramp. here v is the velocity of the granite cube before the collision, u=0. s is the distance traveled by the granite cube along the ramp.
to find a apply F=ma along the ramp.

finally s*sin35=the height you want

ragards
Ashanthi
 

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