Help deriving an equation using chain rule

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SUMMARY

The discussion focuses on deriving the second derivative, r'', from the first derivative, r', using the chain rule in calculus. The user successfully applies the chain rule to obtain r' but seeks clarification on extending this to r''. The relevant equation provided is \(\frac{d}{dt} f(a(t),b(t),c(t))=\frac{\partial f}{\partial a}\dot a+\frac{\partial f}{\partial b} \dot b+\frac{\partial f}{\partial c} \dot c\), which illustrates how to differentiate a function of multiple variables with respect to time.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the chain rule in calculus.
  • Knowledge of functions of multiple variables.
  • Ability to differentiate parametric equations.
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus.
  • Learn how to differentiate parametric equations involving multiple variables.
  • Explore examples of deriving higher-order derivatives using the chain rule.
  • Investigate the implications of the second derivative in physics, particularly in motion analysis.
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives and the chain rule, as well as educators looking for examples of applying these concepts in real-world scenarios.

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Homework Statement



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How does one get the r" equation from r'?

Homework Equations



r = distance
v = r' = ds/dt
a = r'' = dv/dt

chain rule, dy/dt = dy/dx * dx/dt

The Attempt at a Solution



I can easily get to r' from r using the chain rule but how do you derive r" from r'? How do you apply the chain rule when there are 3 variables (sec theta, tan theta and theta dot)?

Help would be appreciated.
 
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[itex]\frac{d}{dt} f(a(t),b(t),c(t))=\frac{\partial f}{\partial a}\dot a+\frac{\partial f}{\partial b} \dot b+\frac{\partial f}{\partial c} \dot c[/itex]
 
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