The discussion focuses on finding the equation of a plane defined by two lines in three-dimensional space. The direction vectors of the lines are identified as <-3, 2, 1> for the first line and <-1, -2, 4> for the second line. The cross product of these direction vectors yields the normal vector of the plane. Using either point (2, -1, 3) or (8, -5, 1) along with the normal vector allows for the formulation of the plane's equation.
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cjavier said:Find an equation of the plane containing the two lines?
The lines are:
(x - 2) / -3 = (y + 1) / 2 = (z - 3) / 1 and (x - 8) / -1 = (y + 5) / -2 = (z -1) / 4
chiro said:Can you find the direction vector of both lines? What does the cross product of two vectors give us with respect to information about the plane?