Help! Exam in one hour! Find equation of plane?

  1. Find an equation of the plane containing the two lines?
    The lines are:

    (x - 2) / -3 = (y + 1) / 2 = (z - 3) / 1 and (x - 8) / -1 = (y + 5) / -2 = (z -1) / 4
     
  2. jcsd
  3. Can you find the direction vector of both lines? What does the cross product of two vectors give us with respect to information about the plane?
     
  4. Before I dive in can I clarify, the direction vector of line one is <-3, 2, 1> and line 2 is <-1, -2, 4> and by taking the cross product I find the normal vector of the plane. With this normal vector, I can take a point, either (2, -1, 3) OR (8, -5, 1) and use the normal vector to find the equation of the plane?
     
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